Protocol of the Lacrosse WS7000-16 rain sensor

Each frame is 46 bits long. It is composed of:

Example 1
0000000000101001111111101101001110111111110111

Example 2
0000000000101001111110111101001110110101111011

Example 3
0000000000101001111111101100011110111010110011

Example 4
0000000000101001111110011100011110110100111101

Example 5
0000000000101001111111000110011110110111110011

When extracting data from the 3 examples, we get:
Example 1
0100 1111 1101 0100 1101 1111 1011 

Example 2
0100 1111 0111 0100 1101 0101 1101 

Example 3
0100 1111 1101 0001 1101 1010 1001 

Example 4
0100 1111 0011 0001 1101 0100 1110 

Example 5
0100 1111 1000 1001 1101 0111 1001 

The 1st bit of each word is LSB, so we have to reverse the 4 bits of each word.

The counter of the rain sensor is coloured in [green] in the following tables:
Example 1
0010 1111 1011 0010 1011 1111 1101 
2 F B 2 B F D 
Check Xor : (2 ^ F ^ B ^ 2 ^ B ^ F) = 0
Check Sum : (const5 + 2 + F + B + 2 + B + F) and F = D
 

Example 2
0010 1111 1110 0010 1011 1010 1011 
2 F E 2 B A B 
Check Xor : (2 ^ F ^ E ^ 2 ^ B ^ A) = 0
Check Sum : (const5 + 2 + F + E + 2 + B + A) and F = B
 

Example 3
0010 1111 1011 1000 1011 0101 1001 
2 F B 8 B 5 9 
Check Xor : (2 ^ F ^ B ^ 8 ^ B ^ 5) = 0
Check Sum : (const5 + 2 + F + B + 8 + B + 5) and F = 9
 

Example 4
0010 1111 1100 1000 1011 0010 0111 
2 F C 8 B 2 7 
Check Xor : (2 ^ F ^ C ^ 8 ^ B ^ 2) = 0
Check Sum : (const5 + 2 + F + C + 8 + B + 2) and F = 7
 

Example 5
0010 1111 0001 1001 1011 1110 1001 
2 F 1 9 B E 9 
Check Xor : (2 ^ F ^ 1 ^ 9 ^ B ^ E) = 0
Check Sum : (const5 + 2 + F + 1 + 9 + B + E) and F = 9
 

 Sensor type is 2
 Sensor Address F
 Data values
 CheckXor
 CheckSum

The first block is the LSB, so the values are repectively:

  1. [hex] B 2 B = [dec] 2859
  2. [hex] B 2 E = [dec] 2862
  3. [hex] B 8 B = [dec] 2955
  4. [hex] B 8 C = [dec] 2956
  5. [hex] B 9 1 = [dec] 2961

I am interested by any comment or more information on the format of these frames. Contact: Jean-Paul ROUBELAT - F6FBB

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